2x^2+7x-4=110

Solution for 2x^2+7x-4=110 equation:

2x^2+7x-4=110

We move all terms to the left:

2x^2+7x-4-(110)=0

We add all the numbers together, and all the variables

2x^2+7x-114=0

a = 2; b = 7; c = -114;
Δ = b2-4ac
Δ = 72-4·2·(-114)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-31}{2*2}=\frac{-38}{4}
=-9+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+31}{2*2}=\frac{24}{4}
=6
$